Optimal. Leaf size=114 \[ \frac{b n \text{PolyLog}\left (2,-d f x^2\right )}{4 d f}+\frac{\left (d f x^2+1\right ) \log \left (d f x^2+1\right ) \left (a+b \log \left (c x^n\right )\right )}{2 d f}-\frac{1}{2} x^2 \left (a+b \log \left (c x^n\right )\right )-\frac{b n \left (d f x^2+1\right ) \log \left (d f x^2+1\right )}{4 d f}+\frac{1}{2} b n x^2 \]
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Rubi [A] time = 0.176585, antiderivative size = 114, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 9, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.375, Rules used = {2454, 2389, 2295, 2376, 2475, 2411, 43, 2351, 2315} \[ \frac{b n \text{PolyLog}\left (2,-d f x^2\right )}{4 d f}+\frac{\left (d f x^2+1\right ) \log \left (d f x^2+1\right ) \left (a+b \log \left (c x^n\right )\right )}{2 d f}-\frac{1}{2} x^2 \left (a+b \log \left (c x^n\right )\right )-\frac{b n \left (d f x^2+1\right ) \log \left (d f x^2+1\right )}{4 d f}+\frac{1}{2} b n x^2 \]
Antiderivative was successfully verified.
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Rule 2454
Rule 2389
Rule 2295
Rule 2376
Rule 2475
Rule 2411
Rule 43
Rule 2351
Rule 2315
Rubi steps
\begin{align*} \int x \left (a+b \log \left (c x^n\right )\right ) \log \left (d \left (\frac{1}{d}+f x^2\right )\right ) \, dx &=-\frac{1}{2} x^2 \left (a+b \log \left (c x^n\right )\right )+\frac{\left (1+d f x^2\right ) \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{2 d f}-(b n) \int \left (-\frac{x}{2}+\frac{\left (1+d f x^2\right ) \log \left (1+d f x^2\right )}{2 d f x}\right ) \, dx\\ &=\frac{1}{4} b n x^2-\frac{1}{2} x^2 \left (a+b \log \left (c x^n\right )\right )+\frac{\left (1+d f x^2\right ) \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{2 d f}-\frac{(b n) \int \frac{\left (1+d f x^2\right ) \log \left (1+d f x^2\right )}{x} \, dx}{2 d f}\\ &=\frac{1}{4} b n x^2-\frac{1}{2} x^2 \left (a+b \log \left (c x^n\right )\right )+\frac{\left (1+d f x^2\right ) \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{2 d f}-\frac{(b n) \operatorname{Subst}\left (\int \frac{(1+d f x) \log (1+d f x)}{x} \, dx,x,x^2\right )}{4 d f}\\ &=\frac{1}{4} b n x^2-\frac{1}{2} x^2 \left (a+b \log \left (c x^n\right )\right )+\frac{\left (1+d f x^2\right ) \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{2 d f}-\frac{(b n) \operatorname{Subst}\left (\int \frac{x \log (x)}{-\frac{1}{d f}+\frac{x}{d f}} \, dx,x,1+d f x^2\right )}{4 d^2 f^2}\\ &=\frac{1}{4} b n x^2-\frac{1}{2} x^2 \left (a+b \log \left (c x^n\right )\right )+\frac{\left (1+d f x^2\right ) \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{2 d f}-\frac{(b n) \operatorname{Subst}\left (\int \left (d f \log (x)+\frac{d f \log (x)}{-1+x}\right ) \, dx,x,1+d f x^2\right )}{4 d^2 f^2}\\ &=\frac{1}{4} b n x^2-\frac{1}{2} x^2 \left (a+b \log \left (c x^n\right )\right )+\frac{\left (1+d f x^2\right ) \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{2 d f}-\frac{(b n) \operatorname{Subst}\left (\int \log (x) \, dx,x,1+d f x^2\right )}{4 d f}-\frac{(b n) \operatorname{Subst}\left (\int \frac{\log (x)}{-1+x} \, dx,x,1+d f x^2\right )}{4 d f}\\ &=\frac{1}{2} b n x^2-\frac{1}{2} x^2 \left (a+b \log \left (c x^n\right )\right )-\frac{b n \left (1+d f x^2\right ) \log \left (1+d f x^2\right )}{4 d f}+\frac{\left (1+d f x^2\right ) \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{2 d f}+\frac{b n \text{Li}_2\left (-d f x^2\right )}{4 d f}\\ \end{align*}
Mathematica [C] time = 0.0481275, size = 267, normalized size = 2.34 \[ -b d f n \left (-\frac{\text{PolyLog}\left (2,-i \sqrt{d} \sqrt{f} x\right )+\log (x) \log \left (1+i \sqrt{d} \sqrt{f} x\right )}{2 d^2 f^2}-\frac{\text{PolyLog}\left (2,i \sqrt{d} \sqrt{f} x\right )+\log (x) \log \left (1-i \sqrt{d} \sqrt{f} x\right )}{2 d^2 f^2}+\frac{\frac{1}{2} x^2 \log (x)-\frac{x^2}{4}}{d f}\right )+\frac{1}{2} a \left (\frac{\left (d f x^2+1\right ) \log \left (d f x^2+1\right )}{d f}-x^2\right )+\frac{1}{4} b x^2 \left (2 \left (\log \left (c x^n\right )-n \log (x)\right )+2 n \log (x)-n\right ) \log \left (d f x^2+1\right )+\frac{b \left (2 \left (\log \left (c x^n\right )-n \log (x)\right )-n\right ) \log \left (d f x^2+1\right )}{4 d f}+\frac{1}{4} b x^2 \left (n-2 \left (\log \left (c x^n\right )-n \log (x)\right )\right ) \]
Antiderivative was successfully verified.
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Maple [C] time = 0.079, size = 820, normalized size = 7.2 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{4} \,{\left (2 \, b x^{2} \log \left (x^{n}\right ) -{\left (b{\left (n - 2 \, \log \left (c\right )\right )} - 2 \, a\right )} x^{2}\right )} \log \left (d f x^{2} + 1\right ) - \int \frac{2 \, b d f x^{3} \log \left (x^{n}\right ) +{\left (2 \, a d f -{\left (d f n - 2 \, d f \log \left (c\right )\right )} b\right )} x^{3}}{2 \,{\left (d f x^{2} + 1\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (b x \log \left (d f x^{2} + 1\right ) \log \left (c x^{n}\right ) + a x \log \left (d f x^{2} + 1\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \log \left (c x^{n}\right ) + a\right )} x \log \left ({\left (f x^{2} + \frac{1}{d}\right )} d\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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